Problem Set 02: Solution Key

Noise and Photometry

Worked Solutions

1. SNR classification

Noise term = 16 × (200 + 6 + 49) = 4080. SNR = 650/√(650+4080) = 9.45 — a secure detection (SNR > 5).

CriterionPoints
Noise term5
SNR value5
Classification5

2. Zero-point application

Rate = 95000/30 = 3166.7 counts/s. m = −2.5×log10(3166.7) + 19.457 = -8.752 + 19.457 = 10.706.

CriterionPoints
Rate computed5
Correct magnitude10

3. Aperture bias

Δm = −2.5×log10(1/0.80) = -0.242 mag. Because only part of the flux is captured, the measured magnitude is too faint (fainter) by 0.242 mag relative to the true value.

CriterionPoints
Correct sign and magnitude10
Correct interpretation5

4. Uncertainty budget

σ_total = √(0.02² + 0.018²) = 0.027 mag. Report: m = 10.71 ± 0.03.

CriterionPoints
Quadrature method8
Correctly combined final report7

Grading Notes

Award full marks for correct method, units, and a numeric result consistent with the arithmetic shown (allow reasonable rounding). Common partial-credit errors: omitting units, failing to combine uncertainties in quadrature, or overstating the confidence of a marginal (SNR 3–5) result.